x^2=10^-7(0.1-x)

Solution for x^2=10^-7(0.1-x) equation:

x^2=10^-7(0.1-x)

We move all terms to the left:

x^2-(10^-7(0.1-x))=0

We add all the numbers together, and all the variables

x^2-(10^-7(-1x+0.1))=0


We calculate terms in parentheses: -(10^-7(-1x+0.1)), so:

10^-7(-1x+0.1)

determiningTheFunctionDomain
-7(-1x+0.1)+10^

We add all the numbers together, and all the variables

-7(-1x+0.1)

We multiply parentheses

7x-0.7

Back to the equation:

-(7x-0.7)


We get rid of parentheses

x^2-7x+0.7=0

a = 1; b = -7; c = +0.7;
Δ = b2-4ac
Δ = -72-4·1·0.7
Δ = 46.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{46.2}}{2*1}=\frac{7-\sqrt{46.2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{46.2}}{2*1}=\frac{7+\sqrt{46.2}}{2}
$